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A 245.9 mL balloon has a pressure of 0.867 atm. If the pressure changes to 1.459 atm, what is the new volume in mL of the balloon? Final answers must have correct significant figures and units to receive full credit. Partial credit may be awarded if appropriate work is shown.

Respuesta :

In this question, we have an example of Boyle's gas law, which is an experimental gas law that shows the relationship between pressure and volume of gases, the formula is:

P1V1 = P2V2

We have:

P1 = 0.867 atm

V1 = 245.9 mL

P2 = 1.459 atm

V2 = ?

Now we add these values into the formula:

0.867 * 245.9 = 1.459 * V2

V2 = 146 mL

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