Given that:
- The probability that an individual is left-handed is 12%.
- There are 30 students in the class.
You need to use this Binomial Distribution Formula, in order to find the probability of finding exactly 4 left-handed students :
[tex]P(x)=\frac{n!}{(n-x)!x!}p^x(1-p)^{n-x}[/tex]Where "n" is the number being sampled, "x" is the number of successes desired, and "p" is the probability of getting a success in one trial.
In this case:
[tex]\begin{gathered} n=30 \\ x=4 \\ p=\frac{12}{100}=0.12 \end{gathered}[/tex]Therefore, by substituting values into the formula and evaluating, you get:
[tex]P(x=4)=\frac{30!}{(30-4)!4!}(0.12)^4(1-0.12)^{30-4}[/tex][tex]P(x=4)\approx0.2047[/tex]Hence, the answer is:
[tex]P(x=4)\approx0.2047[/tex]