Givens.
• The weight force is 763.91 N.
,• The speed is 1.10 m/s.
First, find the mass using the formula for weight force.
[tex]w=mg[/tex]Where w = 763.91 N and g = 9.81 m/s^2.
[tex]\begin{gathered} 763.91N=m\cdot9.81\cdot\frac{m}{s^2} \\ m=\frac{763.91N}{9.81\cdot\frac{m}{s^2}} \\ m\approx77.87\operatorname{kg} \end{gathered}[/tex]Once we have the mass of the woman, we can find the kinetic energy.
Use the kinetic energy formula.
[tex]K=\frac{1}{2}mv^2[/tex]Where m = 77.87 kg and v = 1.10 m/s.
[tex]\begin{gathered} K=\frac{1}{2}\cdot77.87\operatorname{kg}\cdot(1.10\cdot\frac{m}{s})^2 \\ K=38.94\operatorname{kg}\cdot1.21\cdot\frac{m^2}{s^2} \\ K\approx47.12J \end{gathered}[/tex]Therefore, the kinetic energy is 47.12J.
