Given
The y-component of vector K is
[tex]K_y=6\text{ cm}[/tex]
The magnitude of vector K is , K=8 cm
To find
The angle
[tex]\theta[/tex]
Explanation
Resolving K along its y-component we have,
[tex]\begin{gathered} K_y=Ksin\theta \\ \Rightarrow6=8sin\theta \\ \Rightarrow sin\theta=\frac{3}{4} \\ \Rightarrow\theta=48.59\text{ }^o \end{gathered}[/tex]
Conclusion
The angle made with the x-axis is
[tex]48.59^o[/tex]
