BrileiP604713
BrileiP604713
30-10-2022
Mathematics
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EllarieQ562407
EllarieQ562407
30-10-2022
We just have to use the following formula
[tex]\sigma=\sqrt[]{n\cdot P\cdot(1-P)}[/tex]
Where n = 70 and P = 0.7.
[tex]\begin{gathered} \sigma=\sqrt[2]{70\cdot0.7\cdot(1-0.7)}=\sqrt[]{49(0.3)}=\sqrt[]{14.7} \\ \sigma=3.8 \end{gathered}[/tex]
Hence, the standard deviation is 3.8.
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