Respuesta :
Let x and y represent the price of two pieces of production equipments.
Given;
Two pieces of production equipment for a factory were purchased for a total of
$2000.
[tex]x+y=2000------1[/tex]If one piece cost $810 more than the other;
[tex]x-y=810-------2[/tex]We now have a simultaneous equation.
Solving for x and y. let us Add equation 1 to 2 to eliminate y;
[tex]\begin{gathered} x+x+y-y=2000+810 \\ 2x=2810 \\ x=\frac{2810}{2} \\ x=1405 \end{gathered}[/tex]Let us substitute the value of x into equation 1 to get y;
[tex]\begin{gathered} x+y=2000 \\ 1405+y=2000 \\ y=2000-1405 \\ y=595 \end{gathered}[/tex]Therefore, the price of the less expensive piece of equipm
