What is the powder in watts, P, if the voltage is 850 and the resistance is 170?

Solution
From the question
[tex]V=\sqrt[]{PR}[/tex]We are given V = 850 volt and R = 170 ohms
We want to find P
[tex]\begin{gathered} V=\sqrt[]{PR} \\ \text{Square both sides} \\ V^2=PR \\ \text{Divide both sides by R} \\ \frac{V^2}{R}=P \\ \text{Thus,} \\ P=\frac{V^2}{R} \end{gathered}[/tex]Substituting
[tex]\begin{gathered} P=\frac{V^2}{R} \\ P=\frac{(850)^2}{170} \\ P=4250\text{watts} \end{gathered}[/tex]Therefore, the power is
[tex]P=4250\text{watts}[/tex]