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How much spring potential energy (in Joules) can be held inside a spring with a spring constant of 335 N/m and a maximum elastic stretch of 23.7 cm?

How much spring potential energy in Joules can be held inside a spring with a spring constant of 335 Nm and a maximum elastic stretch of 237 cm class=

Respuesta :

The elastic potential energy of a spring is given by:

[tex]U=\frac{1}{2}kx^2[/tex]

Then for this spring we have:

[tex]U=\frac{1}{2}(335)(0.237)^2=9.41[/tex]

Therefore the potential energy is 9.41 J (rounded to two decimals)

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