As given that:
[tex]\frac{CA}{CE}=\frac{CB}{CD}[/tex]
Angle CAB and angle CED are right angles according to given diagram.
E bisects CA and D bisects CD.
E is perpendicular bisector of CA.
AS E and D are bisects CA and CD then they are midpoints of CA and CD respectively.
So according to all these statements ABC ~ EDC
Yes Angle CAB is a right angle.
