We have to find the equation of the line.
We have two points that belong to the line: (6,1) and (-4,3).
We can start calculating the slope of the line as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{3-1}{-4-6}=\frac{2}{-10}=-\frac{1}{5}[/tex]We can now write the equation in slope-point form and rearrange:
[tex]\begin{gathered} y-y_0=m(x-x_0) \\ y-1=-\frac{1}{5}(x-6) \\ y=-\frac{1}{5}x+\frac{6}{5}+1 \\ y=-\frac{1}{5}x+\frac{6}{5}+\frac{5}{5} \\ y=-\frac{1}{5}x+\frac{11}{5} \end{gathered}[/tex]Answer: the equation of the line is y=-(1/5)*x+11/5
