А dº E в b° aº D O A Lct Lb=Ld+Lc ОВ B. Zb+2d=180 h O C. Rotate the figure 180 degrees about point B. Then angle Z CBDis the image of angle Z EBA. D. Reflect the figure across the angle bisector of angle Z ABC. Then angle Z CBD is the image of a E. Reflect the figure across line CE. Then angle Z CBD is the image of angle Z EBA