Respuesta :

Explanation

In the question we have

[tex]4^{2x}=(4^2)^x=16^x[/tex]

Also

[tex](4\times4)^x=16^x[/tex]

And

[tex](4^^x\times4^x)=4^{x+x}=4^{2x}=(4^2)^x=16^x[/tex]

Answer: C,D and E

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