We have two functions:
[tex]\begin{gathered} g\mleft(x\mright)=3x+2 \\ f\mleft(x\mright)=\frac{x-2}{3} \end{gathered}[/tex]We have to calculate f(g(0)).
We can do it like this:
[tex]\begin{gathered} f(g(0))=\frac{g(0)-2}{3} \\ f(g(0))=\frac{\lbrack3(0)+2\rbrack-2}{3} \\ f(g(0))=\frac{0+2-2}{3} \\ f(g(0))=\frac{0}{3} \\ f(g(0))=0 \end{gathered}[/tex]Answer: a) 0
