Problem
(6,8) and (-12,-4) put in standard form
Solution
The standard form for a line is given by:
y =mx +b
We can calculate the slope with this formula:
[tex]m=\frac{-4-8}{-12-6}=\frac{2}{3}[/tex]Then we can find the intercept using one point given for example x=6 and y=8 and we have:
8= 2/3*6 +b
b= 8- 4= 4
And our standard form would be given by:
y= 2/3 x +4
