Given:
• n = 1.33
,• Thickness, t = 215 nm
,• m = 1
Let's find the longest wavelength in nanometers.
Apply the formula for the destructive interference:
[tex]m\lambda=2nt[/tex]Where:
λ is the wavelength
n = 1.33
t = 215 nm
m = 1
Rewrite the formula for λ, plug in the values of the variables and solve:
[tex]\begin{gathered} \lambda=\frac{2nt}{m} \\ \\ \lambda=\frac{2*1.33*215}{1} \\ \\ \lambda=571.9\text{ nm} \end{gathered}[/tex]Therefore, the longest wavelength that gives a minimum at that point is 571.9 nm.
• ANSWER:
571.9 nm
