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The volume V (in cubic feet) of a rectangular box with a square base is described by the equation V=L^2H, where H is the height (in feet) of thr box and L is the length (in feet) of the base. Find thr volume of a 4-foot-tall cardboard box whose square base has a length of 2 feet.

The volume V in cubic feet of a rectangular box with a square base is described by the equation VL2H where H is the height in feet of thr box and L is the lengt class=

Respuesta :

In the given data :

[tex]\text{ The volume of the rectangular box with squre base is V = L}^2H[/tex]

where L is the length and H is the height.

For the 4 foot tall cardoard box,with the square base has length = 2feet

The volume of the carboard is describe as :

[tex]\text{ Volume = L}^2H[/tex]

here we have, length = Square length = 2 feet

Breadth = Height of the cardboard = 4 foot

Substitute the value and simplify:

[tex]\begin{gathered} \text{ Volume = L}^2H \\ \text{ Volume=2}^2\times4 \\ \text{Volume = 4}\times4 \\ \text{Volume =16 f}eet^3 \end{gathered}[/tex]

So, the volume of cardboard is 16 feet³

Answer : Volume of cardboard is 16 feet³

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