Given:
A 490 mL IV bag contains a 30% dextrose solution.
To find:
How much of the original solution must be replaced with a 65% dextrose solution to increase the original concentration to 50%?
Solution:
Let x mL of the solution is replaced with 65% dextrose solution. So, according to the question:
[tex]\text{ dextrose left in the solution + dextrose in 65\% solution = dextrose in final solution}[/tex][tex](520-x)\frac{30}{100}+x(\frac{65}{100})=520(\frac{50}{100})[/tex]Solve the above equation as follows:
[tex]\begin{gathered} 156-0.3x+0.65x=260 \\ 0.35x=104 \\ x=\frac{104}{0.35} \\ x=297.1 \end{gathered}[/tex]Thus, 297.1 mL of the 30% dextrose solution must be replaced with 65% dextrose solution.
