Given
[tex]\int(9x+16\rparen dx[/tex]
Find
Evaluate the integration
Explanation
as we know
[tex]\begin{gathered} \int x^ndx=\frac{x^{n+1}}{n+1} \\ \\ \int adx=ax \end{gathered}[/tex]
so ,
[tex]\begin{gathered} \int(9x+16\rparen dx \\ \frac{9x^2}{2}+16x+C \end{gathered}[/tex]
Final Answer
Hence , on evaluation we obtain .
[tex]\frac{9x^2}{2}+16x+C[/tex]
