ANSWER
0.94A
EXPLANATION
We have the following circuit,
All the resistors of the circuit are connected in parallel, which means that they all have the same voltage drop. Since they are connected in parallel with the voltage source, the voltage drop across all of them is 4.7V.
Using Ohm's law, we can find the current through the 5Ω resistor,
[tex]I_{5\Omega}=\frac{V_{5\Omega}}{R_{5\Omega}}=\frac{4.7V}{5\Omega}=0.94A[/tex]Hence, the current through the 5Ω resistor is 0.94A.
