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The picture below shows a box sliding down a ramp:A right triangle ABC has measure of angle ABC equal to 90 degrees and measure of angle ACB equal to 65 degrees. The length of AB is 12 feet.What is the distance, in feet, that the box has to travel to move from point A to point C? 12 divided by sec 65 degrees 12 cosec 65° 12 sin 65° 12 divided by cot 65 degrees

The picture below shows a box sliding down a rampA right triangle ABC has measure of angle ABC equal to 90 degrees and measure of angle ACB equal to 65 degrees class=

Respuesta :

The length of the hypotenuse of the triangle is the solution to the question.

The length of the hypotenuse can be found using the Sine Trigonometric Ratio given to be:

[tex]\sin\theta=\frac{opp}{hyp}[/tex]

From the image, we have the following parameters:

[tex]\begin{gathered} \theta=65\degree \\ opp=12 \\ hyp=AC \end{gathered}[/tex]

Therefore, we have:

[tex]\sin65=\frac{12}{AC}[/tex]

To solve for AC, we can cross-multiply:

[tex]AC=\frac{12}{\sin65}[/tex]

Recall the identity:

[tex]\cosec x=\frac{1}{\sin x}[/tex]

Therefore, the equation will be:

[tex]AC=12\cosec65[/tex]

The SECOND OPTION is correct.

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