the given expression is,
[tex]\frac{x}{2}=\frac{3x+4}{2x}[/tex][tex]\begin{gathered} 2x^2=6x+8 \\ 2x^2-6x-8=0 \end{gathered}[/tex][tex]2x^2-8x+2x-8=0[/tex][tex]\begin{gathered} 2x(x-4)+2(x-4)=0 \\ (x-4)(2x+2)=0 \end{gathered}[/tex]x-4 = 0
x = 4
2x + 2 = 0
2x = -2
x = -2/2
x = -1
thus, the answer is x = 4 , - 1
