The equation of a line that passes through the point (x1, y1) is calculated as:
[tex]y-y_1=m(x-x_1)[/tex]Where m is the slope and this slope should be the same slope of the line on the graph.
Since the line of the graph is a horizontal line, the slope is 0. So replacing m by 0 and (x1, y1) by (3, -1), we get:
[tex]\begin{gathered} y-(-1)=0(x-3) \\ y+1=0 \\ y=-1 \end{gathered}[/tex]So, the equation of the line that passes through the point(3, -1) and is parallel to the line on the graph is y = -1
Answer: y = -1
