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Robert needs to attach a diagonal brace to arectangular frame in order to make itstructurally sound. If the framework is 3 feetby 6 feet, find how long the brace needs to beto the nearest tenth of a foot.

Respuesta :

Given,

The dimension of the rectangular frame is 3 feet by 6 feet.

Required

The length of the diagonal brass.

The length of the diagonal is calculated as,

[tex]\begin{gathered} Diagonal=\sqrt{(length)^2+(base)^2} \\ =\sqrt{(3)^2+(6)^2} \\ =\sqrt{9+36} \\ =\sqrt{45} \\ =6.7\text{ feet} \end{gathered}[/tex]

Hence, the length of the diagonal is 6.7 feet.

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