3.81L
According to the general gas equation
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]where:
• P1 and P2 are the i,nitial and final pressure
,• T1 and T2 are the ,initial and final temperature
,• V1 and V2 are the ,initial and final volume
At standard temperature and pressure:
[tex]\begin{gathered} P_1=1atm \\ T_1=0^0C=273K \end{gathered}[/tex]Other parameters include
[tex]\begin{gathered} V_1=48.8L \\ P_2=14.0atm \\ T_2=25^0C=25+273 \\ T_2=298K \end{gathered}[/tex]Required
Final volume V2
Substitute the given parameters into the formula to have:
[tex]\begin{gathered} V_2=\frac{P_1V_1T_2}{P_2T_1} \\ V_2=\frac{1\times48.8\times298}{14.0\times273} \\ V_2=\frac{14542.4}{3822} \\ V_2=3.81L \end{gathered}[/tex]Hence the final volume at 14.0atm and 25 degree celsius is 3.81L
