Given the equation of the function:
[tex]g(x)=5(x+2)^2-4[/tex]
The given equation is the equation of a parabola
The general form is:
[tex]g(x)=A(x-h)^2+k[/tex]
where (h,k) is the coordinates of the vertex
Comparing the given equation with the general form
so,
[tex]\begin{gathered} h=-2 \\ k=-4 \end{gathered}[/tex]
so, the coordinates of the vertex = (-2, -4)
