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Kai took five tests this semester. His scores are listed below. 92, 88, 90, 96, 84What is the mean absolute deviation of Kai's test scores?4.03.22.01.6

Respuesta :

the mean can be calculate with this equation:

[tex]m=\frac{x_1+x_2+\cdots}{n}[/tex]

So in our problem will be:

[tex]\begin{gathered} m=\frac{92+88+90+96+84}{5} \\ m=90 \end{gathered}[/tex]

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