Given
Sequence = -10 , -6 , -2 , 2 ,...
Find
sum of the first 50 terms of arithmetic sequence
Explanation
here ,
first term , a = -10
d = -6 - (-10) = 4
n = 50
sum of first 50 terms is given by
[tex]\begin{gathered} \frac{n}{2}[2a+(n-1)d] \\ \frac{50}{2}[2\times(-10)+(50-1)4] \\ 25[-20+196] \\ 25\times176 \\ 4,400 \end{gathered}[/tex]Final Answer
sum of first 50 terms is 4400.
