Respuesta :
let x, y, z be the three test scores
[tex]\frac{x+y+z}{3}=92[/tex]y is the median, y = 90
If the range is 6, then;
z - x = 6
Make z subject of formula from z - x = 6
z = 6+ x
substitute y =90 and z = 6+ x into our first equation and then solve for x
[tex]\frac{x+90+6+x}{3}=\text{ 92}[/tex][tex]\frac{2x+96}{3}=92[/tex]Multiply bothside by 3
[tex]2x\text{ + 96 =276}[/tex]subtract 96 from bothside
[tex]2x\text{ =180}[/tex]Divide bothside by 2
[tex]x=\frac{180}{2}[/tex][tex]x=90[/tex]substitute x =90 into z = 6+ x
z = 6 + 90 =96
The three test scores are;
90, 90, 96
