Given:
[tex]1.8,19.8,2.3,25.9,8.2[/tex]
The sample standard deviation is calculated as,
First, find the mean of the data set.
[tex]\text{Mean}=\frac{1.8+19.8+2.3+25.9+8.2}{5}=11.6[/tex]
Now,
[tex]\begin{gathered} s^2=\frac{\sum^5_{i=1}(x_i-\bar{x})^2}{n-1} \\ s^2=\frac{(1.8-11.6)^2+(19.8-11.6)^2+(2.3-11.6)^2+(25.9-11.6)^2+(8.2-11.6)^2}{5-1} \\ s^2=116.455 \\ s=10.79 \end{gathered}[/tex]
Answer: Standard deviation is 10.79
