[tex]\begin{gathered} \text{remember that the slope of the parallel of a line has the same slope, so the equation has the form} \\ y=-\frac{1}{4}x+b \\ \\ \text{and since it passes through (12,10)} \\ \\ 10=-\frac{1}{4}(12)+b \\ 10=-3+b \\ 10+3=b \\ b=13 \\ \\ \text{And the equation }is\text{ now} \\ y=-\frac{1}{4}x+13 \end{gathered}[/tex]
