Using the information given in the exercise, you need to draw the following Right triangle (It is not drawn to scale):
Where "h" is the height of the building in meters.
To find the height, you can use the following Trigonometry Identify:
[tex]\tan \alpha=\frac{opposite}{adjacent}[/tex]In this case:
[tex]\begin{gathered} \alpha=75\degree \\ opposite=h \\ adjacent=5 \end{gathered}[/tex]Then, you can substitute values and solve for "h". This is (rounded to the nearest tenth):
[tex]\begin{gathered} \tan (75\degree)=\frac{h}{5} \\ \\ 5\cdot\tan (75\degree)=h \\ h=18.66 \\ h\approx18.7 \end{gathered}[/tex]The answer is:
[tex]18.7\text{ }meters[/tex]
