Given:
A die is rolled twice.
To find:
What is the probability that 1 is rolled on the first roll and an even number on the second roll?
Explanation:
[tex]Probability\text{ of event= }\frac{favorable\text{ outcome}}{Total\text{ outcome}}[/tex]Solution:
A die is roll twice.
Each roll of the dice is an independent event. The probability of a 1 on one roll is 1/6 and the probability of an even number on the second roll is 3/6=1/2. Since, each roll is an independent event, the probability of a 1 on one roll and an even number on the second roll is
[tex]\frac{1}{6}\times\frac{1}{2}=\frac{1}{12}[/tex]Hence, these are the required probabilities.
