Find the difference of the complex numbers.(6 + 2i ) - (4 - 8i )A.2 + 10iB.10 - 6iC.2 - 6iD.10 + 10i

Given:
There are two complex numbers given as
[tex]\begin{gathered} \left(6+2i\right) \\ and \\ \left(4-8i\right) \end{gathered}[/tex]Required:
We need to find the difference of both complex numbers
Explanation:
Just take i as x and substitute the numbers
[tex]\begin{gathered} \left(6+2i\right)-(4-8i) \\ 6+2i-4+8i \\ 6-4+i(2+8) \\ 2+10i \end{gathered}[/tex]Final answer:
Difference of both number is
[tex]2+10i[/tex]