Answer:
(a)-4, -7, -10 and -13.
(b) -46
Explanation:
Given the sequence:
[tex]t\mleft(n\mright)=-3n-1[/tex](a) The first four terms are obtained by substituting n=1,2,3 and 4 respectively.
[tex]\begin{gathered} t\mleft(1\mright)=-3(1)-1=-3-1=-4 \\ t(2)=-3(2)-1=-6-1=-7 \\ t(3)=-3(3)-1=-9-1=-10 \\ t(4)=-3(4)-1=-12-1=-13 \end{gathered}[/tex]The first 4 terms of the sequence are -4, -7, -10 and -13.
(b)t(15)
[tex]\begin{gathered} t(15)=-3(15)-1 \\ =-45-1 \\ =-46 \end{gathered}[/tex]