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A scientist expected that a particular chemicalreaction would produce 7.40 micromoles (umol) ofcarbon dioxide. The amount of carbon dioxideproduced was 75.0% of the scientist's expectation.How much carbon dioxide, in mol, was produced?

Respuesta :

Data:

• Product expectation: 7.40 umol

,

• Actual production: 75% of the expected.

Procedure

First, we have to get the proportion of 75 ad follows:

[tex]\frac{75\%}{100\%}=0.75[/tex]

Then, we have to multiply that proportion to the product expectation:

[tex]7.40\times0.75=5.55[/tex]

5.55 umol of carbon dioxide were produced. However, the problem is asking in mol, thus we have to make the following conversion:

[tex]5.55umol\times\frac{1\text{mol}}{1000000umol}=0.00000555\text{mol}=5.55\times10^{-6}mol[/tex]

Answer: 0.00000555

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