In this case the first step is to find the radius of the circle. Use the pythagorean theorem to do this:
[tex]\begin{gathered} r^{}=\sqrt[]{2^2+2^2} \\ r=\sqrt[]{4+4} \\ r=\sqrt[]{8} \\ r^2=8 \end{gathered}[/tex]
Now, use the center and the radius to find the equation of the circle
[tex]\begin{gathered} (x-(-2))^2+(y-2)^2=r^2 \\ (x+2)^2+(y-2)^2=8 \end{gathered}[/tex]
