Given the equation of a line as follows:
[tex]-6x+3y=18[/tex]The x-intercept is the value of x when y = 0
So, substitute with y = 0, then solve for x:
[tex]\begin{gathered} -6x+3(0)=18 \\ -6x=18 \\ x=\frac{18}{-6}=-3 \end{gathered}[/tex]The y-intercept is the value of y when x = 0
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