Given:
The distance covered by bacterium is d=6.82 microns.
The time taken to cover the distance is t=3.5 s.
The speed of bacterium is given as,
[tex]v=\frac{d}{t}[/tex]
Substitute the given values,
[tex]\begin{gathered} v=\frac{(6.82\text{ microns)}}{(3.5\text{ s)}}(\frac{1\times10^{-6}\text{ m}}{1\text{ micron}})(\frac{1\text{ km}}{1000\text{ m}})(\frac{60\text{ s}}{1\text{ min}})(\frac{60\text{ min}}{1\text{ h}}) \\ =7.01\times10^{-6}\text{ km/h} \end{gathered}[/tex]
Thus, the speed of bacterium is
[tex]7.01\times10^{-6}\text{ km/h}[/tex]
