1) Gathering the data:
slope: m= 1.35
24 HCF -----> 49.88
28 HCF ----> ?
2) Since we have the slope we can plug it into the point-slope formula:
[tex]\begin{gathered} (y-y_1)=m(x-x_1) \\ (28-24)=1.35(49.88-x_1) \\ \\ \frac{4}{1.35}=\frac{1.35(49.88-x_1)}{1.35} \\ 2.96=49.88-x_1 \\ 2.96-49.88=-x_1 \\ -46.92=-x_1 \\ x_1=46.92 \end{gathered}[/tex]
Note that we've used the point-slope formula and then plugged it into that so that we could find the first x-coordinate. Considering (49.88, 24) and (46.92, 28) the points.
3) Hence, the answer is $46.92