Given line parallel to x=5 and passes through point (-6,13)
So to find equation of line
Slope of line joining x=5 and the parallel to it will be same m=∞
So the equation of line having m=1/0=∞ and passing through (-6,13) will be
y=m .x+C
[tex]13=\frac{1}{0}\times-6+C[/tex][tex]C=6[/tex]On substituting the value in C we get
[tex]y=\frac{1}{0}x+6[/tex]Hence this is the equation of required line is x=6.
