If a ball is thrown upward from the ground with an initial speed of 64 feet per second, its height h, infeet, after t seconds is-1672 +642-h = -16+2 +64t.What is the maximum height the ball

Respuesta :

Maximum value of a quadratic function

Given a quadratic function in the form:

[tex]f(x)=ax^2+bx+c[/tex]

The maximum or minimum value of the function occurs at the vertex of the parabola that represents the function.

The x-coordinate of the parabola is given by:

[tex]x_m=-\frac{b}{2a}[/tex]

If a is positive, then the function has a minimum value, if a is negative, then the function has a maximum value.

The height of a ball h after t seconds is given by:

[tex]h=-16t^2+64t[/tex]

This is a quadratic function with a=-16, b=64, c=0

The time where the ball reaches its maximum height is:

[tex]t=-\frac{b}{2a}=-\frac{64}{2(-16)}=2\sec [/tex]

Now we substitute this value in the function:

[tex]h=-16\cdot2^2+64\cdot2=-64+128=64ft[/tex]

The maximum height of the ball is 64 ft