To determine the surface area of the pyramid we will use the following formula (another method: compute the area of each triangle and add it to the base area):
[tex]SA=a^2+2a\sqrt{\frac{a^2}{4}+h^2},[/tex]
where a is the side length of the base of the pyramid, and h is its height.
Substituting
[tex]\begin{gathered} a=20m, \\ h=13m \end{gathered}[/tex]
in the above formula, we get:
[tex]SA=(20m)^2+2(20m)\sqrt{\frac{(20m)^2}{4}+(13m)^2}.[/tex]
Simplifying the above result, we get:
[tex]SA≈1056m^2.[/tex]
Answer:
[tex]1056m^2.[/tex]
