Answer
1.15 mol
Explanation
Given:
Mass of Ru₃P₇ = 600 grams
What to find:
The number of moles of Ru₃P₇ present in 600 grams of Ru₃P₇.
Step-by-step solution:
Step 1: Find the molar mass of Ru₃P₇.
From the Periodic Table, the atomic masses of (Ru = 101.07, P = 30.97).
Molar mass of Ru₃P₇ = (3 x 101.07) + (7 x 30.97)
Molar mass of Ru₃P₇ = 303.21 + 216.79
Molar mass of Ru₃P₇ = 520 g/mol
Step 2: Find the moles of Ru₃P₇.
Using the mole formula below, the number of moles can be calculated:
[tex]\begin{gathered} Moles=\frac{Mass}{Molar\text{ }mass} \\ \\ Moles=\frac{600\text{ }g}{520\text{ }g\text{/}mol}=1.15\text{ }mol \end{gathered}[/tex]Therefore, the number of moles of Ru₃P₇ present in 600 grams of Ru₃P₇ = 1.15 mol.
