Given:
Find-:
The surface area of the box
Explanation-:
The surface area of the box is:
[tex]=ABCD+EFGH+EDCH+ABGF+ADEF+BCGH[/tex]
So,
[tex]\begin{gathered} ABCD=EFGH \\ \\ EDCH=ABGF \\ \\ ADEF=BCGH \end{gathered}[/tex]
So, surface area becomes:
[tex]=2(ABCD+EDCH+ADEF)[/tex]
The formula of area is:
[tex]\text{ Area }=\text{ Length }\times\text{ Width}[/tex][tex]\begin{gathered} =2((15\times10)+(10\times2)+(15\times2)) \\ \\ =2(150+20+30) \\ \\ =2(200) \\ \\ =400\text{ in}^2 \end{gathered}[/tex]
The wrapping paper area is 400in²
