ANSWER
[tex]0.42A[/tex]EXPLANATION
To find the current throughout the circuit, we have to apply the relationship between voltage and current using Ohm's law:
[tex]V=IR[/tex]where V = voltage; I = current; R = resistance
Since the resistors are in series, the total resistance of the circuit is the sum of the individual resistances of the resistors.
Hence, the resistance is:
[tex]\begin{gathered} R=R_1+R_2_{} \\ R=13+13 \\ R=26\Omega \end{gathered}[/tex]Therefore, the current throughout the circuit is:
[tex]\begin{gathered} 11=I\cdot26 \\ I=\frac{11}{26} \\ I\approxeq0.42A \end{gathered}[/tex]That is the answer.
