Respuesta :
[tex]\frac{-8s^4t}{16st^4}\text{ = }\frac{-s^3}{2t^3}[/tex]
Here, we want to divide the terms given in the question
We proceed as follows;
[tex]\frac{-8s^4t}{16st^4}[/tex]We pair up similar terms and multiply it by the rest
Kindly recall the law of indices which states the following;
[tex]\frac{a^x}{a^y^{}\text{ }}=a^{x-y}[/tex]Thus, we have that;
[tex]\begin{gathered} \frac{-8}{16}\times\frac{s^4}{s}\times\frac{t}{t^4} \\ \\ =\text{ }\frac{-1}{2}\text{ }\times s^3\text{ }\times\text{ }\frac{1}{t^3} \\ \\ =\text{ }\frac{-s^3}{2t^3} \end{gathered}[/tex]