Given:
There are given the piecewise function:
[tex]f(x)=\begin{cases}9x-3\text{ x<0}{} \\ 9x-6\text{ x}\ge0{}\end{cases}[/tex]
Explanation:
First, find the value for f(-1).
Then,
To find the value for f ( -1 ), first, we need to check the value of x which is less than 0
Then,
In the given piecewise function, the value of x which is less than o is;
[tex]f(x)=9x-3[/tex]
Ten,
Put the value -1 for x into the above function:
So,
[tex]\begin{gathered} f(x)=9x-3 \\ f(-1)=9(-1)-3 \\ f(-1)=-9-3 \\ f(-1)=-12 \end{gathered}[/tex]
Now,
For the f(0):
Then,
We need to check the function whose value of x is equal to 0.
Then,
The function is:
[tex]f(x)=9x-6[/tex]
Then,
Put the value 0 for x into the above function:
[tex]\begin{gathered} f(x)=9x-6 \\ f(0)=9(0)-6 \\ f(0)=-6 \end{gathered}[/tex]
Now,
For the function f(2):
Then,
We need to check the value of x has greater than 0:
Then,
The function is:
[tex]f(x)=9x-6[/tex]
Then,
Put the value 6 for x into the above function:;
Then,
[tex]\begin{gathered} f(x)=9x-6 \\ f(2)=9(2)-6 \\ f(2)=18-6 \\ f(2)=12 \end{gathered}[/tex]
Final answer:
Hence, the values are shown below:
[tex]\begin{gathered} f(-1)=-12 \\ f(0)=-6 \\ f(2)=12 \end{gathered}[/tex]
