Given
[tex]v(t)=19,900(0.90)^t[/tex]
Procedure
Initial value
[tex]\begin{gathered} v(0)=19,900(0.90)^0 \\ v(0)=19,900 \end{gathered}[/tex]19,900 initial value of the car
value after 12 years
[tex]\begin{gathered} v(12)=19,900(0.90)^{12} \\ v(12)=19,900\cdot0.2824 \\ v(12)=5,620.34 \end{gathered}[/tex]$5,620.34 value of the car after 12 years