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Craig shoots a basketball at an angle of 55" from the horizontal. It leaves his hands 6 feet from the ground with a velocity of 21 ft/s.Step 2 of 2: Determine the height of the ball when it is 2 feet away horizontally. Round to the nearest tenth.AnswerHow to enter your answer (opens in new window)okay

Craig shoots a basketball at an angle of 55 from the horizontal It leaves his hands 6 feet from the ground with a velocity of 21 ftsStep 2 of 2 Determine the he class=
Craig shoots a basketball at an angle of 55 from the horizontal It leaves his hands 6 feet from the ground with a velocity of 21 ftsStep 2 of 2 Determine the he class=

Respuesta :

8.422 ft

Step 1

given:

[tex]\begin{gathered} x=12t \\ y=-16t^2+17.2t+6 \end{gathered}[/tex]

hence

a)find the time wich the distance horizontally is 2 ft

so

let

[tex]x=2[/tex]

now ,replace and solve for t

[tex]\begin{gathered} x=12t \\ 2=12t \\ divide\text{ both sides by 12} \\ \frac{2}{12}=\frac{12t}{12} \\ \frac{1}{6}=t \\ t=\frac{1}{6}\text{ seconds} \end{gathered}[/tex]

b)now, find the heigth for the given time

let

[tex]t=\text{ }\frac{1}{6}\text{ sec}[/tex]

now, replace in the parametric equation

[tex]\begin{gathered} y=-16t^2+17.2t+6 \\ y=-16(\frac{1}{6})^2+17.2(\frac{1}{6})+6 \\ y=-\frac{16}{36}+\frac{17.2}{6}+6 \\ y=-0.4444+2.8666+6 \\ y=8.422 \end{gathered}[/tex]

therefore, the answer is

8.422 ft

I hope this helps you

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