As per given by the question,
There are given that Latoya, Josh, and Alonzo have a total of $82 in their wallets.
now,
Let L, J, and A be the amounts that each person has.
So,
[tex]L+J+A=82\ldots\text{ (1)}[/tex]Now,
According to the question,
Jos has 2 times what Alonzo has,
So,
[tex]L+2A+A=82\ldots\text{. (2)}[/tex]Now,
Latoya has $6 less than Alonzo,
So,
[tex](A-6)+2A+A=82_{}\ldots\ldots\text{.}(3)[/tex]Then,
From the equation (3),
[tex]\begin{gathered} (A-6)+2A+A=82 \\ A-6+3A=82 \\ 4A-6=82 \\ 4A=82+6 \\ 4A=88 \\ A=\frac{88}{4} \\ A=22 \end{gathered}[/tex]Now,
From the question,
Jose has 2 times what Alonzo has,
So,
[tex]\begin{gathered} A(\text{Alonzo)}=22 \\ J(\text{Jose)}=22\times2 \\ =44 \end{gathered}[/tex]Now,
Latoya has 6 less than Alonzo,
So,
[tex]\begin{gathered} A=22 \\ L=22-6 \\ L=16 \end{gathered}[/tex]Then,
From the equation (1).
[tex]\begin{gathered} L+J+A=82 \\ 16+44+22=82 \\ 82=82. \end{gathered}[/tex]Hence,
Amount in Latoya wallets is$16.
Amounts in Jose's wallets is $44.
Amount in Alonzo wallet's is $22.
